24/3x^2-2=0

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Solution for 24/3x^2-2=0 equation:



24/3x^2-2=0
Domain of the equation: 3x^2!=0
x^2!=0/3
x^2!=√0
x!=0
x∈R
We multiply all the terms by the denominator
-2*3x^2+24=0
Wy multiply elements
-6x^2+24=0
a = -6; b = 0; c = +24;
Δ = b2-4ac
Δ = 02-4·(-6)·24
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24}{2*-6}=\frac{-24}{-12} =+2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24}{2*-6}=\frac{24}{-12} =-2 $

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